AN5265

AN5265 PANASONIC | Alldatasheet

Document overview

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Technical content

The AN5265 is a semiconductor integrated circuit de- signed for TV sound output circuit. n Features

• DC volume adjustment method employed. Controlled with DC voltage.
• Fin-attached 9-lead SIP package employed AN5265 TV Sound Output Circuit n Block Diagram 1 2 3 4 5 6 7 8 9 Mute DC Volume Control Audio Output Amp. Vol GND OutputFeed backInput V CC1 V CC2 ø 3.3–0.10.1–0.05 5.6–0.25 –0.25 1.7 1.7–0.25 0.45 + 0.1– 0.05 3.75–0.25 0.5 –0.1 1.2 –0.25 2.54 Unit : mm 9-lead HSIP Package (HSIP009-P-0000) 15.0 19.9–0.1 18.3–0.25 5.8–0.25 1.5–0.25 –0.3 –0.25 22.3–0.3 Supply Voltage 1 Sound Input Mute Volume adjustment Filter Pin No. Pin Description Feedback GND Sound output Supply voltage 2 n Pin Descriptions

ICs for Audio Common UseAN5265 Param eter Sym bol R ating U nit V 1 – 7 V 9 – 7 V 3 – 7 V 4 – 7 V 6 – 7 Tstg V oltage C urrent Storage Tem perature – 55 ~ + 150 V A (peak) V V V m A (peak) 14.4 V 1 – 7 PDPow er D issipation 1.6 W ToprO perating A m bient Tem perature – 20 ~ + 70 ˚C –10 V 9 – 7 –1.2 1.2 V Supply V oltage C ircuit C urrent C ircuit V oltage n Absolute M axim um R atings (Ta= 25˚C ) 7.1 9.5 11.9 m A f= 1kH z, V 4= 12V , V 8= 0V rm s 2.45 2.65 2.85 V V 3 – 7 V 2 – 7 V 5 – 7 V 6 – 7 C ircuit C urrent M uting O peration V oltage C ircuit V oltage C ircuit V oltage C ircuit V oltage 5.4 8.5 8.8 V V V m in.C ondition typ. m ax. U nitSym bol V 8 – 7C ircuit V oltage 8.8 V Pom ax.M ax. O utput Pow er 2.0 2.3 W G V f= 1kH z, V i= 0.1V rm s, V 4= 12VV oltage G ain 28.5 30.5 32.5 dB TH D f= 1kH z, PO = 1W ,V 4= 12VTotal H arm onics D istortion 0.8 1.2 % A tt f= 1kH z, V i= 0.1V rm s, V 4= R atio betw een 12 and 0 VM ax. A ttenuation A m ount –95 –85 dB V no V i= 0V rm s, V 4= 0VO utput N oise V oltage 0.6 1.0 m V rm s n Electrical C haracteristics (Ta= 25˚C ) Pin1= Pin4 = 12V , Pin7= 0V , Pin9 = 18V Pin1= 12V , Pin4 = Pin7= 0V , Pin9 = 18V Pin1= 12V , Pin4 = Pin7= 0V , Pin9 = 18V Pin1= 12V , Pin4 = Pin7= 0V , Pin9 = 18V Pin1= 12V , Pinr= Pin4 = 0V , Pin9 =18V , Pin6 – 8 : 10kΩ f= 1kH z, TH D = 10% , V 4= 12V , R L= 16Ω Param eter n Application Circuit PD – Ta Pow er D issipation PD (W ) A m bient Tem perature Ta (˚C ) Tc=Ta W ithout heat sink –20 0 20 40 60 80 100 120 140 160 180 A N 5265 10kΩ100µF V C C =18V 10µF 0.047µF 100µF 100µF 10µF 1µF 4.7Ω 680Ω R L =16Ω V C C =12V A F Input M ute 21 3 4 5 6 7 8 9